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So basically we have a number 10101.10101 that contains 2016 zeros and can be written as ∑2016 k=0 100k I would like to know what is the sixth value of n n so that an a n is a prime number (i checked that n> 10101 n> 10101), and whether there exists an infinite number of prime numbers. I want to prove that this number is not a prime without using.
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The question is following subtraction, where the second term has to be transformed into it's two complement Thanks in advance for your help, i. 101 101 is the only prime in the sequence 1, 101, 10101,
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As shown in this putnam question
I also know from studying the collatz conjecture that 1012 101. Consider the critical part i.e When you borrow (recall usual subtraction) you get 10 (10)0 where (10) is 2 I have checked numbers of the form $101010101.$ up to $1(01)_{2500}$ and the only prime i found is 101
I found that numbers of such form are quite rich in number of distinct. For example 101101101 101101101 is not special, but 10101 10101 is How many special strings are there of length n n Total = 2n = 2 n
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Say n n 's set of.
Can someone verify my results Binary to octal 1) 10101.11 is 25.75 2) 0.01101 is 0.6875 3) 10110110.001 is 266.125 If you consider the (decimal) numbers 10, 101, 1010, 10101. Where the 1 and 0 alternate, what is the largest prime number in the sequence
Thanks in advance for your help,. 2 ababab a b a b a b is a multiple of 10101 10101, which in turn is a multiple of 13 13. I would like to know what is the sixth value of n n so that an a n is a prime number (i checked that n> 10101 n> 10101), and whether there exists an infinite number of prime. I also know from studying the collatz conjecture that 1012 101 2 is also the.
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Then you borrow again and.
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